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210113222113 is a prime number
BaseRepresentation
bin1100001110101110111…
…0010101010111100001
3202002100011002121011101
43003223232111113201
511420302441101423
6240305155314401
721115541630404
oct3035356252741
9662304077141
10210113222113
1181121488703
123487a5aba01
1316a765cc482
14a2532b7d3b
1556eb2497ad
hex30ebb955e1

210113222113 has 2 divisors, whose sum is σ = 210113222114. Its totient is φ = 210113222112.

The previous prime is 210113222029. The next prime is 210113222131. The reversal of 210113222113 is 311222311012.

Together with next prime (210113222131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 182612638224 + 27500583889 = 427332^2 + 165833^2 .

It is a cyclic number.

It is not a de Polignac number, because 210113222113 - 29 = 210113221601 is a prime.

It is a super-2 number, since 2×2101132221132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (210113222213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105056611056 + 105056611057.

It is an arithmetic number, because the mean of its divisors is an integer number (105056611057).

Almost surely, 2210113222113 is an apocalyptic number.

It is an amenable number.

210113222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

210113222113 is an equidigital number, since it uses as much as digits as its factorization.

210113222113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 210113222113 its reverse (311222311012), we get a palindrome (521335533125).

The spelling of 210113222113 in words is "two hundred ten billion, one hundred thirteen million, two hundred twenty-two thousand, one hundred thirteen".