Base | Representation |
---|---|
bin | 11110100101101001110… |
… | …000111001100010111001 |
3 | 21102221122221010020110221 |
4 | 132211221300321202321 |
5 | 233414410414342131 |
6 | 4245352430540041 |
7 | 304602565246453 |
oct | 36455160714271 |
9 | 7387587106427 |
10 | 2102013434041 |
11 | 740505869764 |
12 | 29b474067621 |
13 | 1232b0242ab1 |
14 | 73a490a52d3 |
15 | 39a28d80411 |
hex | 1e969c398b9 |
2102013434041 has 16 divisors (see below), whose sum is σ = 2163405937600. Its totient is φ = 2040865865280.
The previous prime is 2102013434033. The next prime is 2102013434069. The reversal of 2102013434041 is 1404343102012.
It is a cyclic number.
It is not a de Polignac number, because 2102013434041 - 23 = 2102013434033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2102013433997 and 2102013434015.
It is not an unprimeable number, because it can be changed into a prime (2102013434011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41527150 + ... + 41577736.
It is an arithmetic number, because the mean of its divisors is an integer number (135212871100).
Almost surely, 22102013434041 is an apocalyptic number.
It is an amenable number.
2102013434041 is a deficient number, since it is larger than the sum of its proper divisors (61392503559).
2102013434041 is a wasteful number, since it uses less digits than its factorization.
2102013434041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52984.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2102013434041 its reverse (1404343102012), we get a palindrome (3506356536053).
The spelling of 2102013434041 in words is "two trillion, one hundred two billion, thirteen million, four hundred thirty-four thousand, forty-one".
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