Base | Representation |
---|---|
bin | 101111110011010000111001… |
… | …010001100100100001011011 |
3 | 1000120100220000020221221210212 |
4 | 233303100321101210201123 |
5 | 210023411112122040323 |
6 | 2023042444121201335 |
7 | 62165455442352254 |
oct | 5763207121444133 |
9 | 1016326006857725 |
10 | 210231020111963 |
11 | 60a93525161834 |
12 | 1b6b421b33024b |
13 | 903c91425abb6 |
14 | 39cb342943b2b |
15 | 19488d08d5b78 |
hex | bf343946485b |
210231020111963 has 2 divisors, whose sum is σ = 210231020111964. Its totient is φ = 210231020111962.
The previous prime is 210231020111941. The next prime is 210231020112053. The reversal of 210231020111963 is 369111020132012.
210231020111963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 210231020111963 - 216 = 210231020046427 is a prime.
It is not a weakly prime, because it can be changed into another prime (210231020111263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105115510055981 + 105115510055982.
It is an arithmetic number, because the mean of its divisors is an integer number (105115510055982).
Almost surely, 2210231020111963 is an apocalyptic number.
210231020111963 is a deficient number, since it is larger than the sum of its proper divisors (1).
210231020111963 is an equidigital number, since it uses as much as digits as its factorization.
210231020111963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 32.
Adding to 210231020111963 its reverse (369111020132012), we get a palindrome (579342040243975).
The spelling of 210231020111963 in words is "two hundred ten trillion, two hundred thirty-one billion, twenty million, one hundred eleven thousand, nine hundred sixty-three".
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