Base | Representation |
---|---|
bin | 11110100101111011101… |
… | …000011010101000000011 |
3 | 21102222102211011221020201 |
4 | 132211323220122220003 |
5 | 233421014134401011 |
6 | 4245442255550031 |
7 | 304613165233204 |
oct | 36457350325003 |
9 | 7388384157221 |
10 | 2102313200131 |
11 | 740649aa3431 |
12 | 29b53852b317 |
13 | 12332a38b291 |
14 | 73a76c175ab |
15 | 39a45344cc1 |
hex | 1e97ba1aa03 |
2102313200131 has 4 divisors (see below), whose sum is σ = 2102316310264. Its totient is φ = 2102310090000.
The previous prime is 2102313200107. The next prime is 2102313200149. The reversal of 2102313200131 is 1310023132012.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2102313200131 - 213 = 2102313191939 is a prime.
It is a super-2 number, since 2×21023132001312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2102313200099 and 2102313200108.
It is not an unprimeable number, because it can be changed into a prime (2102313200101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65565 + ... + 2051566.
It is an arithmetic number, because the mean of its divisors is an integer number (525579077566).
Almost surely, 22102313200131 is an apocalyptic number.
2102313200131 is a deficient number, since it is larger than the sum of its proper divisors (3110133).
2102313200131 is an equidigital number, since it uses as much as digits as its factorization.
2102313200131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3110132.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2102313200131 its reverse (1310023132012), we get a palindrome (3412336332143).
The spelling of 2102313200131 in words is "two trillion, one hundred two billion, three hundred thirteen million, two hundred thousand, one hundred thirty-one".
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