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21024454152113 is a prime number
BaseRepresentation
bin1001100011111001000110…
…00111110000111110110001
32202102220210100200120102022
410301330203013300332301
510223431040230331423
6112414300110001225
74266652400443016
oct461744307607661
982386710616368
1021024454152113
11677646a2983a5
12243681b1a6215
13b9679c99a469
1452983635d70d
15266d633ebdc8
hex131f231f0fb1

21024454152113 has 2 divisors, whose sum is σ = 21024454152114. Its totient is φ = 21024454152112.

The previous prime is 21024454152101. The next prime is 21024454152131. The reversal of 21024454152113 is 31125145442012.

Together with next prime (21024454152131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11416512441889 + 9607941710224 = 3378833^2 + 3099668^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21024454152113 is a prime.

It is not a weakly prime, because it can be changed into another prime (21024454152173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10512227076056 + 10512227076057.

It is an arithmetic number, because the mean of its divisors is an integer number (10512227076057).

Almost surely, 221024454152113 is an apocalyptic number.

It is an amenable number.

21024454152113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21024454152113 is an equidigital number, since it uses as much as digits as its factorization.

21024454152113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 35.

Adding to 21024454152113 its reverse (31125145442012), we get a palindrome (52149599594125).

The spelling of 21024454152113 in words is "twenty-one trillion, twenty-four billion, four hundred fifty-four million, one hundred fifty-two thousand, one hundred thirteen".