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21041014011 = 37013671337
BaseRepresentation
bin10011100110001001…
…000110010011111011
32000022101101021000020
4103212021012103323
5321042444422021
613355513541523
71343262445113
oct234611062373
960271337006
1021041014011
118a18116286
1240b27148a3
131ca4275064
14103866c043
1583234e7c6
hex4e62464fb

21041014011 has 4 divisors (see below), whose sum is σ = 28054685352. Its totient is φ = 14027342672.

The previous prime is 21041013979. The next prime is 21041014013. The reversal of 21041014011 is 11041014012.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21041014011 - 25 = 21041013979 is a prime.

It is a super-2 number, since 2×210410140112 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (21041014013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3506835666 + ... + 3506835671.

It is an arithmetic number, because the mean of its divisors is an integer number (7013671338).

Almost surely, 221041014011 is an apocalyptic number.

21041014011 is a deficient number, since it is larger than the sum of its proper divisors (7013671341).

21041014011 is an equidigital number, since it uses as much as digits as its factorization.

21041014011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7013671340.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 21041014011 its reverse (11041014012), we get a palindrome (32082028023).

Subtracting from 21041014011 its reverse (11041014012), we obtain a palindrome (9999999999).

The spelling of 21041014011 in words is "twenty-one billion, forty-one million, fourteen thousand, eleven".

Divisors: 1 3 7013671337 21041014011