Base | Representation |
---|---|
bin | 11110100111101000001… |
… | …011110111101010011001 |
3 | 21110011010202011011122222 |
4 | 132213220023313222121 |
5 | 233433231403332213 |
6 | 4250343115153425 |
7 | 305006261404244 |
oct | 36475013675231 |
9 | 7404122134588 |
10 | 2104134433433 |
11 | 7413a403aa1a |
12 | 29b966445875 |
13 | 12355a7a3c16 |
14 | 73baaa5a25b |
15 | 39b00194808 |
hex | 1e9e82f7a99 |
2104134433433 has 2 divisors, whose sum is σ = 2104134433434. Its totient is φ = 2104134433432.
The previous prime is 2104134433421. The next prime is 2104134433441. The reversal of 2104134433433 is 3343344314012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1708426756624 + 395707676809 = 1307068^2 + 629053^2 .
It is a cyclic number.
It is not a de Polignac number, because 2104134433433 - 210 = 2104134432409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2104134433393 and 2104134433402.
It is not a weakly prime, because it can be changed into another prime (2104134433403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052067216716 + 1052067216717.
It is an arithmetic number, because the mean of its divisors is an integer number (1052067216717).
Almost surely, 22104134433433 is an apocalyptic number.
It is an amenable number.
2104134433433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104134433433 is an equidigital number, since it uses as much as digits as its factorization.
2104134433433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 2104134433433 its reverse (3343344314012), we get a palindrome (5447478747445).
The spelling of 2104134433433 in words is "two trillion, one hundred four billion, one hundred thirty-four million, four hundred thirty-three thousand, four hundred thirty-three".
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