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2104420141331 is a prime number
BaseRepresentation
bin11110100111111001001…
…101110000100100010011
321110011212122202122012222
4132213321031300210103
5233434323024010311
64250431323011255
7305016331030004
oct36477115604423
97404778678188
102104420141331
11741530342552
1229ba26069b2b
131235a4a39651
1473bd698d1ab
1539b1a2cdadb
hex1e9f9370913

2104420141331 has 2 divisors, whose sum is σ = 2104420141332. Its totient is φ = 2104420141330.

The previous prime is 2104420141267. The next prime is 2104420141387. The reversal of 2104420141331 is 1331410244012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2104420141331 - 26 = 2104420141267 is a prime.

It is a super-2 number, since 2×21044201413312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2104420141331.

It is not a weakly prime, because it can be changed into another prime (2104420144331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052210070665 + 1052210070666.

It is an arithmetic number, because the mean of its divisors is an integer number (1052210070666).

Almost surely, 22104420141331 is an apocalyptic number.

2104420141331 is a deficient number, since it is larger than the sum of its proper divisors (1).

2104420141331 is an equidigital number, since it uses as much as digits as its factorization.

2104420141331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 2104420141331 its reverse (1331410244012), we get a palindrome (3435830385343).

The spelling of 2104420141331 in words is "two trillion, one hundred four billion, four hundred twenty million, one hundred forty-one thousand, three hundred thirty-one".