Base | Representation |
---|---|
bin | 10011101001001101… |
… | …101000110010001001 |
3 | 2000102222022211010001 |
4 | 103221031220302021 |
5 | 321144142113213 |
6 | 13404554123001 |
7 | 1344456410254 |
oct | 235115506211 |
9 | 60388284101 |
10 | 21092535433 |
11 | 8a44206072 |
12 | 4107a20461 |
13 | 1cb1b43ac8 |
14 | 104144009b |
15 | 836b2a1dd |
hex | 4e9368c89 |
21092535433 has 2 divisors, whose sum is σ = 21092535434. Its totient is φ = 21092535432.
The previous prime is 21092535337. The next prime is 21092535463. The reversal of 21092535433 is 33453529012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20536896249 + 555639184 = 143307^2 + 23572^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21092535433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21092535392 and 21092535401.
It is not a weakly prime, because it can be changed into another prime (21092535463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10546267716 + 10546267717.
It is an arithmetic number, because the mean of its divisors is an integer number (10546267717).
Almost surely, 221092535433 is an apocalyptic number.
It is an amenable number.
21092535433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21092535433 is an equidigital number, since it uses as much as digits as its factorization.
21092535433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 21092535433 in words is "twenty-one billion, ninety-two million, five hundred thirty-five thousand, four hundred thirty-three".
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