Base | Representation |
---|---|
bin | 11110101101000110100… |
… | …001110011101111000001 |
3 | 21110201022101020011110120 |
4 | 132231012201303233001 |
5 | 234032301111210423 |
6 | 4253154244250453 |
7 | 305305032601353 |
oct | 36550641635701 |
9 | 7421271204416 |
10 | 2110012210113 |
11 | 74393a9805a5 |
12 | 2a0b269a0a29 |
13 | 123c86447aa2 |
14 | 741a75310d3 |
15 | 39d461d7ee3 |
hex | 1eb46873bc1 |
2110012210113 has 4 divisors (see below), whose sum is σ = 2813349613488. Its totient is φ = 1406674806740.
The previous prime is 2110012210063. The next prime is 2110012210133. The reversal of 2110012210113 is 3110122100112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2110012210113 - 216 = 2110012144577 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2110012210092 and 2110012210101.
It is not an unprimeable number, because it can be changed into a prime (2110012210133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351668701683 + ... + 351668701688.
It is an arithmetic number, because the mean of its divisors is an integer number (703337403372).
Almost surely, 22110012210113 is an apocalyptic number.
It is an amenable number.
2110012210113 is a deficient number, since it is larger than the sum of its proper divisors (703337403375).
2110012210113 is an equidigital number, since it uses as much as digits as its factorization.
2110012210113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 703337403374.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 2110012210113 its reverse (3110122100112), we get a palindrome (5220134310225).
The spelling of 2110012210113 in words is "two trillion, one hundred ten billion, twelve million, two hundred ten thousand, one hundred thirteen".
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