Base | Representation |
---|---|
bin | 11110101101000110100… |
… | …001110110011100100001 |
3 | 21110201022101020201200211 |
4 | 132231012201312130201 |
5 | 234032301112034332 |
6 | 4253154244414121 |
7 | 305305032645625 |
oct | 36550641663441 |
9 | 7421271221624 |
10 | 2110012221217 |
11 | 74393a98897a |
12 | 2a0b269a7341 |
13 | 123c8644cb64 |
14 | 741a7535185 |
15 | 39d461db447 |
hex | 1eb46876721 |
2110012221217 has 2 divisors, whose sum is σ = 2110012221218. Its totient is φ = 2110012221216.
The previous prime is 2110012221199. The next prime is 2110012221241. The reversal of 2110012221217 is 7121222100112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2065359882496 + 44652338721 = 1437136^2 + 211311^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110012221217 - 219 = 2110011696929 is a prime.
It is a super-2 number, since 2×21100122212172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2110012221287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055006110608 + 1055006110609.
It is an arithmetic number, because the mean of its divisors is an integer number (1055006110609).
Almost surely, 22110012221217 is an apocalyptic number.
It is an amenable number.
2110012221217 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110012221217 is an equidigital number, since it uses as much as digits as its factorization.
2110012221217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 2110012221217 its reverse (7121222100112), we get a palindrome (9231234321329).
The spelling of 2110012221217 in words is "two trillion, one hundred ten billion, twelve million, two hundred twenty-one thousand, two hundred seventeen".
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