Base | Representation |
---|---|
bin | 1100010010000010101… |
… | …0001100100101001001 |
3 | 202011122001020011010211 |
4 | 3010200222030211021 |
5 | 11424112320024433 |
6 | 240533242441121 |
7 | 21146544466246 |
oct | 3044052144511 |
9 | 664561204124 |
10 | 211001329993 |
11 | 81537828263 |
12 | 34a87b031a1 |
13 | 16b885c0cac |
14 | a2d921a5cd |
15 | 574e1c78cd |
hex | 3120a8c949 |
211001329993 has 2 divisors, whose sum is σ = 211001329994. Its totient is φ = 211001329992.
The previous prime is 211001329937. The next prime is 211001330051. The reversal of 211001329993 is 399923100112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 210963838864 + 37491129 = 459308^2 + 6123^2 .
It is a cyclic number.
It is not a de Polignac number, because 211001329993 - 221 = 210999232841 is a prime.
It is a super-2 number, since 2×2110013299932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211001329093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500664996 + 105500664997.
It is an arithmetic number, because the mean of its divisors is an integer number (105500664997).
Almost surely, 2211001329993 is an apocalyptic number.
It is an amenable number.
211001329993 is a deficient number, since it is larger than the sum of its proper divisors (1).
211001329993 is an equidigital number, since it uses as much as digits as its factorization.
211001329993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 40.
The spelling of 211001329993 in words is "two hundred eleven billion, one million, three hundred twenty-nine thousand, nine hundred ninety-three".
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