Base | Representation |
---|---|
bin | 11110101101000111000… |
… | …000010111010001001001 |
3 | 21110201022221022002221012 |
4 | 132231013000113101021 |
5 | 234032310134014402 |
6 | 4253155132053305 |
7 | 305305160641625 |
oct | 36550700272111 |
9 | 7421287262835 |
10 | 2110020219977 |
11 | 74394445151a |
12 | 2a0b29604235 |
13 | 123c87cc0857 |
14 | 741a8618185 |
15 | 39d46c6b452 |
hex | 1eb47017449 |
2110020219977 has 2 divisors, whose sum is σ = 2110020219978. Its totient is φ = 2110020219976.
The previous prime is 2110020219959. The next prime is 2110020220001. The reversal of 2110020219977 is 7799120200112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1582415559481 + 527604660496 = 1257941^2 + 726364^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110020219977 - 222 = 2110016025673 is a prime.
It is not a weakly prime, because it can be changed into another prime (2110020219577) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055010109988 + 1055010109989.
It is an arithmetic number, because the mean of its divisors is an integer number (1055010109989).
Almost surely, 22110020219977 is an apocalyptic number.
It is an amenable number.
2110020219977 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110020219977 is an equidigital number, since it uses as much as digits as its factorization.
2110020219977 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31752, while the sum is 41.
The spelling of 2110020219977 in words is "two trillion, one hundred ten billion, twenty million, two hundred nineteen thousand, nine hundred seventy-seven".
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