Base | Representation |
---|---|
bin | 1001100110000111101011… |
… | …01011100111100011110001 |
3 | 2202201020101001111000102221 |
4 | 10303003311223213203301 |
5 | 10231204322302210342 |
6 | 112513355515041041 |
7 | 4305332323630204 |
oct | 463036553474361 |
9 | 82636331430387 |
10 | 21101001210097 |
11 | 67a5980098a96 |
12 | 2449622740181 |
13 | ba0a7b630c03 |
14 | 52d4186a993b |
15 | 268d436a6a67 |
hex | 1330f5ae78f1 |
21101001210097 has 2 divisors, whose sum is σ = 21101001210098. Its totient is φ = 21101001210096.
The previous prime is 21101001210089. The next prime is 21101001210119. The reversal of 21101001210097 is 79001210010112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11371941917361 + 9729059292736 = 3372231^2 + 3119144^2 .
It is a cyclic number.
It is not a de Polignac number, because 21101001210097 - 23 = 21101001210089 is a prime.
It is not a weakly prime, because it can be changed into another prime (21101001210077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550500605048 + 10550500605049.
It is an arithmetic number, because the mean of its divisors is an integer number (10550500605049).
Almost surely, 221101001210097 is an apocalyptic number.
It is an amenable number.
21101001210097 is a deficient number, since it is larger than the sum of its proper divisors (1).
21101001210097 is an equidigital number, since it uses as much as digits as its factorization.
21101001210097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 25.
The spelling of 21101001210097 in words is "twenty-one trillion, one hundred one billion, one million, two hundred ten thousand, ninety-seven".
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