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211012000210113 = 370337333403371
BaseRepresentation
bin101111111110101000001111…
…010100001101110011000001
31000200010112212002210120110020
4233332220033110031303001
5210124210034023210423
62024441324043124053
762306054034561354
oct5776501724156301
91020115762716406
10211012000210113
1161264761057783
121b7bb657b13629
1390984668bc27b
143a1706cc3029b
15195dd8e00b4e3
hexbfea0f50dcc1

211012000210113 has 4 divisors (see below), whose sum is σ = 281349333613488. Its totient is φ = 140674666806740.

The previous prime is 211012000210103. The next prime is 211012000210127. The reversal of 211012000210113 is 311012000210112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211012000210113 - 210 = 211012000209089 is a prime.

It is a super-2 number, since 2×2110120002101132 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211012000210092 and 211012000210101.

It is not an unprimeable number, because it can be changed into a prime (211012000210103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35168666701683 + ... + 35168666701688.

It is an arithmetic number, because the mean of its divisors is an integer number (70337333403372).

Almost surely, 2211012000210113 is an apocalyptic number.

It is an amenable number.

211012000210113 is a deficient number, since it is larger than the sum of its proper divisors (70337333403375).

211012000210113 is an equidigital number, since it uses as much as digits as its factorization.

211012000210113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70337333403374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 211012000210113 its reverse (311012000210112), we get a palindrome (522024000420225).

Subtracting 211012000210113 from its reverse (311012000210112), we obtain a palindrome (99999999999999).

The spelling of 211012000210113 in words is "two hundred eleven trillion, twelve billion, two hundred ten thousand, one hundred thirteen".

Divisors: 1 3 70337333403371 211012000210113