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21101214122137 is a prime number
BaseRepresentation
bin1001100110001000000100…
…10111110100000010011001
32202201020220220010001212001
410303010002113310002121
510231210241303402022
6112513433002321001
74305340520433052
oct463040227640231
982636826101761
1021101214122137
1167a5a7a29aa56
122449681ab9161
13ba0ab3789376
1452d438a8d729
15268d57211b27
hex1331025f4099

21101214122137 has 2 divisors, whose sum is σ = 21101214122138. Its totient is φ = 21101214122136.

The previous prime is 21101214122119. The next prime is 21101214122179. The reversal of 21101214122137 is 73122141210112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13627054122256 + 7474159999881 = 3691484^2 + 2733891^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21101214122137 is a prime.

It is a super-3 number, since 3×211012141221373 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (21101214122437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550607061068 + 10550607061069.

It is an arithmetic number, because the mean of its divisors is an integer number (10550607061069).

Almost surely, 221101214122137 is an apocalyptic number.

It is an amenable number.

21101214122137 is a deficient number, since it is larger than the sum of its proper divisors (1).

21101214122137 is an equidigital number, since it uses as much as digits as its factorization.

21101214122137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 21101214122137 its reverse (73122141210112), we get a palindrome (94223355332249).

The spelling of 21101214122137 in words is "twenty-one trillion, one hundred one billion, two hundred fourteen million, one hundred twenty-two thousand, one hundred thirty-seven".