Base | Representation |
---|---|
bin | 101111111110101000011100… |
… | …011011000100100100000011 |
3 | 1000200010120102102120200220111 |
4 | 233332220130123010210003 |
5 | 210124211011322023412 |
6 | 2024441401540252151 |
7 | 62306062344653212 |
oct | 5776503433044403 |
9 | 1020116372520814 |
10 | 211012220111107 |
11 | 612648641a2638 |
12 | 1b7bb6b96a1057 |
13 | 90984a03238bc |
14 | 3a17090113079 |
15 | 195dda34972a7 |
hex | bfea1c6c4903 |
211012220111107 has 2 divisors, whose sum is σ = 211012220111108. Its totient is φ = 211012220111106.
The previous prime is 211012220111093. The next prime is 211012220111177. The reversal of 211012220111107 is 701111022210112.
211012220111107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211012220111107 is a prime.
It is not a weakly prime, because it can be changed into another prime (211012220111177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506110055553 + 105506110055554.
It is an arithmetic number, because the mean of its divisors is an integer number (105506110055554).
Almost surely, 2211012220111107 is an apocalyptic number.
211012220111107 is a deficient number, since it is larger than the sum of its proper divisors (1).
211012220111107 is an equidigital number, since it uses as much as digits as its factorization.
211012220111107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 211012220111107 its reverse (701111022210112), we get a palindrome (912123242321219).
The spelling of 211012220111107 in words is "two hundred eleven trillion, twelve billion, two hundred twenty million, one hundred eleven thousand, one hundred seven".
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