Base | Representation |
---|---|
bin | 1001100110001000000101… |
… | …10101111010010011010001 |
3 | 2202201020221102221220212101 |
4 | 10303010002311322103101 |
5 | 10231210300313341423 |
6 | 112513433443400401 |
7 | 4305340644463645 |
oct | 463040265722321 |
9 | 82636842856771 |
10 | 21101222012113 |
11 | 67a5a837998a1 |
12 | 2449684683101 |
13 | ba0ab52bc6a9 |
14 | 52d439b44c25 |
15 | 268d57c6e7ad |
hex | 133102d7a4d1 |
21101222012113 has 2 divisors, whose sum is σ = 21101222012114. Its totient is φ = 21101222012112.
The previous prime is 21101222012099. The next prime is 21101222012141. The reversal of 21101222012113 is 31121022210112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15801801621904 + 5299420390209 = 3975148^2 + 2302047^2 .
It is a cyclic number.
It is not a de Polignac number, because 21101222012113 - 233 = 21092632077521 is a prime.
It is not a weakly prime, because it can be changed into another prime (21101222012183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550611006056 + 10550611006057.
It is an arithmetic number, because the mean of its divisors is an integer number (10550611006057).
Almost surely, 221101222012113 is an apocalyptic number.
It is an amenable number.
21101222012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21101222012113 is an equidigital number, since it uses as much as digits as its factorization.
21101222012113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 21101222012113 its reverse (31121022210112), we get a palindrome (52222244222225).
The spelling of 21101222012113 in words is "twenty-one trillion, one hundred one billion, two hundred twenty-two million, twelve thousand, one hundred thirteen".
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