211014331131 has 4 divisors (see below), whose sum is σ = 281352441512. Its totient is φ = 140676220752.

The previous prime is 211014331127. The next prime is 211014331139. The reversal of 211014331131 is 131133410112.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 211014331131 - 2² = 211014331127 is a prime.

It is a super-2 number, since 2×211014331131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211014331098 and 211014331107.

It is not an unprimeable number, because it can be changed into a prime (211014331139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35169055186 + ... + 35169055191.

It is an arithmetic number, because the mean of its divisors is an integer number (70338110378).

Almost surely, 2^211014331131 is an apocalyptic number.

211014331131 is a deficient number, since it is larger than the sum of its proper divisors (70338110381).

211014331131 is an equidigital number, since it uses as much as digits as its factorization.

211014331131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70338110380.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 211014331131 its reverse (131133410112), we get a palindrome (342147741243).

The spelling of 211014331131 in words is "two hundred eleven billion, fourteen million, three hundred thirty-one thousand, one hundred thirty-one".