Base | Representation |
---|---|
bin | 1001100110001001110000… |
… | …11111000110011001010001 |
3 | 2202201100021011110010220012 |
4 | 10303010320133012121101 |
5 | 10231214121213031001 |
6 | 112514103033324305 |
7 | 4305402153331115 |
oct | 463047037063121 |
9 | 82640234403805 |
10 | 21102122002001 |
11 | 67a63a5814597 |
12 | 2449895b66695 |
13 | ba0bc98b15a1 |
14 | 52d4c349b745 |
15 | 268dabc982bb |
hex | 1331387c6651 |
21102122002001 has 2 divisors, whose sum is σ = 21102122002002. Its totient is φ = 21102122002000.
The previous prime is 21102122001973. The next prime is 21102122002021. The reversal of 21102122002001 is 10020022120112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16992079401025 + 4110042600976 = 4122145^2 + 2027324^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21102122002001 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (21102122002021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551061001000 + 10551061001001.
It is an arithmetic number, because the mean of its divisors is an integer number (10551061001001).
Almost surely, 221102122002001 is an apocalyptic number.
It is an amenable number.
21102122002001 is a deficient number, since it is larger than the sum of its proper divisors (1).
21102122002001 is an equidigital number, since it uses as much as digits as its factorization.
21102122002001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 21102122002001 its reverse (10020022120112), we get a palindrome (31122144122113).
The spelling of 21102122002001 in words is "twenty-one trillion, one hundred two billion, one hundred twenty-two million, two thousand, one".
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