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211023213003 = 3223447023667
BaseRepresentation
bin1100010010000111110…
…1101011000111001011
3202011200120101220222200
43010201331223013023
511424133420304003
6240535343451243
721150231500151
oct3044175530713
9664616356880
10211023213003
1181549114299
1234a932b6b23
1316b8ccb3515
14a2dc0b53d1
15575109b6a3
hex3121f6b1cb

211023213003 has 6 divisors (see below), whose sum is σ = 304811307684. Its totient is φ = 140682141996.

The previous prime is 211023212971. The next prime is 211023213007. The reversal of 211023213003 is 300312320112.

It is not a de Polignac number, because 211023213003 - 25 = 211023212971 is a prime.

It is a super-2 number, since 2×2110232130032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (211023213007) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11723511825 + ... + 11723511842.

It is an arithmetic number, because the mean of its divisors is an integer number (50801884614).

Almost surely, 2211023213003 is an apocalyptic number.

211023213003 is a deficient number, since it is larger than the sum of its proper divisors (93788094681).

211023213003 is a wasteful number, since it uses less digits than its factorization.

211023213003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23447023673 (or 23447023670 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 211023213003 its reverse (300312320112), we get a palindrome (511335533115).

The spelling of 211023213003 in words is "two hundred eleven billion, twenty-three million, two hundred thirteen thousand, three".

Divisors: 1 3 9 23447023667 70341071001 211023213003