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2110301213131 is a prime number
BaseRepresentation
bin11110101101010111110…
…000010001000111001011
321110202001112001001002001
4132231113300101013023
5234033344102310011
64253243050451431
7305315142226636
oct36552760210713
97422045031061
102110301213131
11743a79023871
122a0ba7733b77
131240012952a7
14741d3a80c1d
1539d617737c1
hex1eb57c111cb

2110301213131 has 2 divisors, whose sum is σ = 2110301213132. Its totient is φ = 2110301213130.

The previous prime is 2110301213101. The next prime is 2110301213183. The reversal of 2110301213131 is 1313121030112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2110301213131 - 29 = 2110301212619 is a prime.

It is a super-2 number, since 2×21103012131312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2110301213099 and 2110301213108.

It is not a weakly prime, because it can be changed into another prime (2110301213101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055150606565 + 1055150606566.

It is an arithmetic number, because the mean of its divisors is an integer number (1055150606566).

Almost surely, 22110301213131 is an apocalyptic number.

2110301213131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110301213131 is an equidigital number, since it uses as much as digits as its factorization.

2110301213131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 2110301213131 its reverse (1313121030112), we get a palindrome (3423422243243).

The spelling of 2110301213131 in words is "two trillion, one hundred ten billion, three hundred one million, two hundred thirteen thousand, one hundred thirty-one".