Base | Representation |
---|---|
bin | 1001100110001111111010… |
… | …01101001010001011010011 |
3 | 2202201122210011202021011012 |
4 | 10303013331031022023103 |
5 | 10231242401114113301 |
6 | 112515410332441135 |
7 | 4305550020334151 |
oct | 463077515121323 |
9 | 82648704667135 |
10 | 21105422410451 |
11 | 67a7839808285 |
12 | 244a4573191ab |
13 | ba13045a77b2 |
14 | 52d7179423d1 |
15 | 2690018cbebb |
hex | 1331fd34a2d3 |
21105422410451 has 2 divisors, whose sum is σ = 21105422410452. Its totient is φ = 21105422410450.
The previous prime is 21105422410307. The next prime is 21105422410493. The reversal of 21105422410451 is 15401422450112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21105422410451 is a prime.
It is a super-2 number, since 2×211054224104512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21105422419451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10552711205225 + 10552711205226.
It is an arithmetic number, because the mean of its divisors is an integer number (10552711205226).
Almost surely, 221105422410451 is an apocalyptic number.
21105422410451 is a deficient number, since it is larger than the sum of its proper divisors (1).
21105422410451 is an equidigital number, since it uses as much as digits as its factorization.
21105422410451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12800, while the sum is 32.
Adding to 21105422410451 its reverse (15401422450112), we get a palindrome (36506844860563).
The spelling of 21105422410451 in words is "twenty-one trillion, one hundred five billion, four hundred twenty-two million, four hundred ten thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •