2111000113 has 2 divisors, whose sum is σ = 2111000114. Its totient is φ = 2111000112.

The previous prime is 2111000107. The next prime is 2111000131. The reversal of 2111000113 is 3110001112.

Together with next prime (2111000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1352989089 + 758011024 = 36783^2 + 27532^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111000113 - 2¹³ = 2110991921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2111000113.

It is not a weakly prime, because it can be changed into another prime (2111000153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055500056 + 1055500057.

It is an arithmetic number, because the mean of its divisors is an integer number (1055500057).

Almost surely, 2^2111000113 is an apocalyptic number.

It is an amenable number.

2111000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111000113 is an equidigital number, since it uses as much as digits as its factorization.

2111000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 2111000113 is about 45945.6212603552. The cubic root of 2111000113 is about 1282.8112270654.

Adding to 2111000113 its reverse (3110001112), we get a palindrome (5221001225).

Subtracting 2111000113 from its reverse (3110001112), we obtain a palindrome (999000999).

The spelling of 2111000113 in words is "two billion, one hundred eleven million, one hundred thirteen", and thus it is an aban number.