Base | Representation |
---|---|
bin | 1100010010011010101… |
… | …0010001001010110001 |
3 | 202011220001200100000001 |
4 | 3010212222101022301 |
5 | 11424314103341311 |
6 | 240551240430001 |
7 | 21152206332112 |
oct | 3044652211261 |
9 | 664801610001 |
10 | 211102012081 |
11 | 815896451a4 |
12 | 34ab5778301 |
13 | 16ba34130ac |
14 | a308748209 |
15 | 5757e644c1 |
hex | 3126a912b1 |
211102012081 has 2 divisors, whose sum is σ = 211102012082. Its totient is φ = 211102012080.
The previous prime is 211102012067. The next prime is 211102012111. The reversal of 211102012081 is 180210201112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125730522225 + 85371489856 = 354585^2 + 292184^2 .
It is a cyclic number.
It is not a de Polignac number, because 211102012081 - 25 = 211102012049 is a prime.
It is a super-2 number, since 2×2111020120812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211102010081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105551006040 + 105551006041.
It is an arithmetic number, because the mean of its divisors is an integer number (105551006041).
Almost surely, 2211102012081 is an apocalyptic number.
It is an amenable number.
211102012081 is a deficient number, since it is larger than the sum of its proper divisors (1).
211102012081 is an equidigital number, since it uses as much as digits as its factorization.
211102012081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 211102012081 its reverse (180210201112), we get a palindrome (391312213193).
The spelling of 211102012081 in words is "two hundred eleven billion, one hundred two million, twelve thousand, eighty-one".
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