Base | Representation |
---|---|
bin | 11110101110000010101… |
… | …011010000101111111101 |
3 | 21110210220201001022122202 |
4 | 132232002223100233331 |
5 | 234041332424234323 |
6 | 4253442333121245 |
7 | 305342035110260 |
oct | 36560253205775 |
9 | 7423821038582 |
10 | 2111021321213 |
11 | 744308557712 |
12 | 2a1168929225 |
13 | 1240b752504c |
14 | 74261570cd7 |
15 | 39da4ab8d28 |
hex | 1eb82ad0bfd |
2111021321213 has 16 divisors (see below), whose sum is σ = 2541963755520. Its totient is φ = 1712600069616.
The previous prime is 2111021321183. The next prime is 2111021321219. The reversal of 2111021321213 is 3121231201112.
It is a cyclic number.
It is not a de Polignac number, because 2111021321213 - 214 = 2111021304829 is a prime.
It is a super-2 number, since 2×21110213212132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2111021321219) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7324445 + ... + 7607202.
It is an arithmetic number, because the mean of its divisors is an integer number (158872734720).
Almost surely, 22111021321213 is an apocalyptic number.
It is an amenable number.
2111021321213 is a deficient number, since it is larger than the sum of its proper divisors (430942434307).
2111021321213 is a wasteful number, since it uses less digits than its factorization.
2111021321213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14932736.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2111021321213 its reverse (3121231201112), we get a palindrome (5232252522325).
The spelling of 2111021321213 in words is "two trillion, one hundred eleven billion, twenty-one million, three hundred twenty-one thousand, two hundred thirteen".
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