Base | Representation |
---|---|
bin | 11110101110000010101… |
… | …101110110111111000001 |
3 | 21110210220202022220200021 |
4 | 132232002231312333001 |
5 | 234041333113031423 |
6 | 4253442355453441 |
7 | 305342043644353 |
oct | 36560255667701 |
9 | 7423822286607 |
10 | 2111022002113 |
11 | 744308982242 |
12 | 2a1168bb7281 |
13 | 1240b7702c4b |
14 | 742616ab0d3 |
15 | 39da4ba095d |
hex | 1eb82b76fc1 |
2111022002113 has 2 divisors, whose sum is σ = 2111022002114. Its totient is φ = 2111022002112.
The previous prime is 2111022002101. The next prime is 2111022002123. The reversal of 2111022002113 is 3112002201112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1225422432144 + 885599569969 = 1106988^2 + 941063^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111022002113 is a prime.
It is a super-3 number, since 3×21110220021133 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2111022002123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055511001056 + 1055511001057.
It is an arithmetic number, because the mean of its divisors is an integer number (1055511001057).
Almost surely, 22111022002113 is an apocalyptic number.
It is an amenable number.
2111022002113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111022002113 is an equidigital number, since it uses as much as digits as its factorization.
2111022002113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2111022002113 its reverse (3112002201112), we get a palindrome (5223024203225).
The spelling of 2111022002113 in words is "two trillion, one hundred eleven billion, twenty-two million, two thousand, one hundred thirteen".
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