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2111022002113 is a prime number
BaseRepresentation
bin11110101110000010101…
…101110110111111000001
321110210220202022220200021
4132232002231312333001
5234041333113031423
64253442355453441
7305342043644353
oct36560255667701
97423822286607
102111022002113
11744308982242
122a1168bb7281
131240b7702c4b
14742616ab0d3
1539da4ba095d
hex1eb82b76fc1

2111022002113 has 2 divisors, whose sum is σ = 2111022002114. Its totient is φ = 2111022002112.

The previous prime is 2111022002101. The next prime is 2111022002123. The reversal of 2111022002113 is 3112002201112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1225422432144 + 885599569969 = 1106988^2 + 941063^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111022002113 is a prime.

It is a super-3 number, since 3×21110220021133 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2111022002123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055511001056 + 1055511001057.

It is an arithmetic number, because the mean of its divisors is an integer number (1055511001057).

Almost surely, 22111022002113 is an apocalyptic number.

It is an amenable number.

2111022002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111022002113 is an equidigital number, since it uses as much as digits as its factorization.

2111022002113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2111022002113 its reverse (3112002201112), we get a palindrome (5223024203225).

The spelling of 2111022002113 in words is "two trillion, one hundred eleven billion, twenty-two million, two thousand, one hundred thirteen".