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21112001114131 is a prime number
BaseRepresentation
bin1001100110011100001010…
…10100111011000000010011
32202202021202122202001001001
410303032011110323000103
510231344334241123011
6112522415221122431
74306202032363234
oct463160524730023
982667678661031
1021112001114131
1167aa605270774
12244b792559417
13ba1b12523975
1452db7d55308b
152692892277c1
hex13338553b013

21112001114131 has 2 divisors, whose sum is σ = 21112001114132. Its totient is φ = 21112001114130.

The previous prime is 21112001114107. The next prime is 21112001114173. The reversal of 21112001114131 is 13141110021112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21112001114131 - 219 = 21112000589843 is a prime.

It is a super-2 number, since 2×211120011141312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21112001114099 and 21112001114108.

It is not a weakly prime, because it can be changed into another prime (21112001154131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556000557065 + 10556000557066.

It is an arithmetic number, because the mean of its divisors is an integer number (10556000557066).

Almost surely, 221112001114131 is an apocalyptic number.

21112001114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21112001114131 is an equidigital number, since it uses as much as digits as its factorization.

21112001114131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 21112001114131 its reverse (13141110021112), we get a palindrome (34253111135243).

The spelling of 21112001114131 in words is "twenty-one trillion, one hundred twelve billion, one million, one hundred fourteen thousand, one hundred thirty-one".