Base | Representation |
---|---|
bin | 1001100110011100001010… |
… | …10100111011000000010011 |
3 | 2202202021202122202001001001 |
4 | 10303032011110323000103 |
5 | 10231344334241123011 |
6 | 112522415221122431 |
7 | 4306202032363234 |
oct | 463160524730023 |
9 | 82667678661031 |
10 | 21112001114131 |
11 | 67aa605270774 |
12 | 244b792559417 |
13 | ba1b12523975 |
14 | 52db7d55308b |
15 | 2692892277c1 |
hex | 13338553b013 |
21112001114131 has 2 divisors, whose sum is σ = 21112001114132. Its totient is φ = 21112001114130.
The previous prime is 21112001114107. The next prime is 21112001114173. The reversal of 21112001114131 is 13141110021112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21112001114131 - 219 = 21112000589843 is a prime.
It is a super-2 number, since 2×211120011141312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21112001114099 and 21112001114108.
It is not a weakly prime, because it can be changed into another prime (21112001154131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556000557065 + 10556000557066.
It is an arithmetic number, because the mean of its divisors is an integer number (10556000557066).
Almost surely, 221112001114131 is an apocalyptic number.
21112001114131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112001114131 is an equidigital number, since it uses as much as digits as its factorization.
21112001114131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 21112001114131 its reverse (13141110021112), we get a palindrome (34253111135243).
The spelling of 21112001114131 in words is "twenty-one trillion, one hundred twelve billion, one million, one hundred fourteen thousand, one hundred thirty-one".
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