Base | Representation |
---|---|
bin | 110000000000001100111011… |
… | …110000111001110001010001 |
3 | 1000200111212221011110120112202 |
4 | 300000030323300321301101 |
5 | 210132443001222011121 |
6 | 2025003124431532545 |
7 | 62316632246554013 |
oct | 6000147360716121 |
9 | 1020455834416482 |
10 | 211120120110161 |
11 | 612a65a3a03979 |
12 | 1b8185b108a155 |
13 | 90a57077323a2 |
14 | 3a1c3a844a1b3 |
15 | 1961abb02740b |
hex | c0033bc39c51 |
211120120110161 has 2 divisors, whose sum is σ = 211120120110162. Its totient is φ = 211120120110160.
The previous prime is 211120120110101. The next prime is 211120120110173. The reversal of 211120120110161 is 161011021021112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 166269574437136 + 44850545673025 = 12894556^2 + 6697055^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211120120110161 is a prime.
It is not a weakly prime, because it can be changed into another prime (211120120110101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560060055080 + 105560060055081.
It is an arithmetic number, because the mean of its divisors is an integer number (105560060055081).
Almost surely, 2211120120110161 is an apocalyptic number.
It is an amenable number.
211120120110161 is a deficient number, since it is larger than the sum of its proper divisors (1).
211120120110161 is an equidigital number, since it uses as much as digits as its factorization.
211120120110161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 211120120110161 its reverse (161011021021112), we get a palindrome (372131141131273).
The spelling of 211120120110161 in words is "two hundred eleven trillion, one hundred twenty billion, one hundred twenty million, one hundred ten thousand, one hundred sixty-one".
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