Base | Representation |
---|---|
bin | 110000000000001101000000… |
… | …100001101100111101010011 |
3 | 1000200111220010201210222201102 |
4 | 300000031000201230331103 |
5 | 210132443132200332403 |
6 | 2025003140404255015 |
7 | 62316634236656561 |
oct | 6000150041547523 |
9 | 1020456121728642 |
10 | 211120200011603 |
11 | 612a6635018023 |
12 | 1b8186139a146b |
13 | 90a571b15994c |
14 | 3a1c3b4cc8a31 |
15 | 1961ac305bb88 |
hex | c0034086cf53 |
211120200011603 has 2 divisors, whose sum is σ = 211120200011604. Its totient is φ = 211120200011602.
The previous prime is 211120200011593. The next prime is 211120200011621. The reversal of 211120200011603 is 306110002021112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211120200011603 - 240 = 210020688383827 is a prime.
It is a super-2 number, since 2×2111202000116032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211120200011663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560100005801 + 105560100005802.
It is an arithmetic number, because the mean of its divisors is an integer number (105560100005802).
Almost surely, 2211120200011603 is an apocalyptic number.
211120200011603 is a deficient number, since it is larger than the sum of its proper divisors (1).
211120200011603 is an equidigital number, since it uses as much as digits as its factorization.
211120200011603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 211120200011603 its reverse (306110002021112), we get a palindrome (517230202032715).
The spelling of 211120200011603 in words is "two hundred eleven trillion, one hundred twenty billion, two hundred million, eleven thousand, six hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •