Base | Representation |
---|---|
bin | 110000000000001101000000… |
… | …100001101111000010100011 |
3 | 1000200111220010201211102102021 |
4 | 300000031000201233002203 |
5 | 210132443132201121011 |
6 | 2025003140404402311 |
7 | 62316634240023463 |
oct | 6000150041570243 |
9 | 1020456121742367 |
10 | 211120200020131 |
11 | 612a6635023476 |
12 | 1b8186139a6397 |
13 | 90a571b1607ac |
14 | 3a1c3b4ccbba3 |
15 | 1961ac305e471 |
hex | c0034086f0a3 |
211120200020131 has 2 divisors, whose sum is σ = 211120200020132. Its totient is φ = 211120200020130.
The previous prime is 211120200020111. The next prime is 211120200020173. The reversal of 211120200020131 is 131020002021112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211120200020131 - 215 = 211120199987363 is a prime.
It is a super-2 number, since 2×2111202000201312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211120200020111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560100010065 + 105560100010066.
It is an arithmetic number, because the mean of its divisors is an integer number (105560100010066).
Almost surely, 2211120200020131 is an apocalyptic number.
211120200020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211120200020131 is an equidigital number, since it uses as much as digits as its factorization.
211120200020131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 211120200020131 its reverse (131020002021112), we get a palindrome (342140202041243).
The spelling of 211120200020131 in words is "two hundred eleven trillion, one hundred twenty billion, two hundred million, twenty thousand, one hundred thirty-one".
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