Base | Representation |
---|---|
bin | 11110101110001101111… |
… | …110111001111110000001 |
3 | 21110211101221000000200201 |
4 | 132232031332321332001 |
5 | 234042230010121121 |
6 | 4253513231045201 |
7 | 305346530402365 |
oct | 36561576717601 |
9 | 7424357000621 |
10 | 2111211020161 |
11 | 7443a5644301 |
12 | 2a1200370801 |
13 | 124117913749 |
14 | 7427c8312a5 |
15 | 39db658ae91 |
hex | 1eb8dfb9f81 |
2111211020161 has 2 divisors, whose sum is σ = 2111211020162. Its totient is φ = 2111211020160.
The previous prime is 2111211020153. The next prime is 2111211020183. The reversal of 2111211020161 is 1610201121112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1764431365761 + 346779654400 = 1328319^2 + 588880^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111211020161 - 23 = 2111211020153 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111211020461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055605510080 + 1055605510081.
It is an arithmetic number, because the mean of its divisors is an integer number (1055605510081).
Almost surely, 22111211020161 is an apocalyptic number.
It is an amenable number.
2111211020161 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111211020161 is an equidigital number, since it uses as much as digits as its factorization.
2111211020161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 2111211020161 its reverse (1610201121112), we get a palindrome (3721412141273).
The spelling of 2111211020161 in words is "two trillion, one hundred eleven billion, two hundred eleven million, twenty thousand, one hundred sixty-one".
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