Base | Representation |
---|---|
bin | 10011101010011000… |
… | …011001101100100001 |
3 | 2000111100012112212221 |
4 | 103222120121230201 |
5 | 321214201300213 |
6 | 13410534151041 |
7 | 1345115116225 |
oct | 235230315441 |
9 | 60440175787 |
10 | 21112134433 |
11 | 8a54282095 |
12 | 41124b2481 |
13 | 1cb5c16850 |
14 | 1043ca2785 |
15 | 8386ec38d |
hex | 4ea619b21 |
21112134433 has 32 divisors (see below), whose sum is σ = 23630745600. Its totient is φ = 18740284416.
The previous prime is 21112134413. The next prime is 21112134457. The reversal of 21112134433 is 33443121112.
It is a cyclic number.
It is not a de Polignac number, because 21112134433 - 29 = 21112133921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21112134398 and 21112134407.
It is not an unprimeable number, because it can be changed into a prime (21112134413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7109373 + ... + 7112341.
It is an arithmetic number, because the mean of its divisors is an integer number (738460800).
Almost surely, 221112134433 is an apocalyptic number.
It is an amenable number.
21112134433 is a deficient number, since it is larger than the sum of its proper divisors (2518611167).
21112134433 is a wasteful number, since it uses less digits than its factorization.
21112134433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3241.
The product of its digits is 1728, while the sum is 25.
Adding to 21112134433 its reverse (33443121112), we get a palindrome (54555255545).
The spelling of 21112134433 in words is "twenty-one billion, one hundred twelve million, one hundred thirty-four thousand, four hundred thirty-three".
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