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211122100121 = 418635043167
BaseRepresentation
bin1100010010011111011…
…0111001011110011001
3202011221110110220121112
43010213312321132121
511424334224200441
6240553235150105
721152542145612
oct3044766713631
9664843426545
10211122100121
1181599a15689
1234b00445335
1316ba76275ca
14a30b296c09
155759ad14eb
hex3127db9799

211122100121 has 4 divisors (see below), whose sum is σ = 211127185152. Its totient is φ = 211117015092.

The previous prime is 211122100117. The next prime is 211122100127. The reversal of 211122100121 is 121001221112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211122100121 - 22 = 211122100117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211122100096 and 211122100105.

It is not an unprimeable number, because it can be changed into a prime (211122100127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2479721 + ... + 2563446.

It is an arithmetic number, because the mean of its divisors is an integer number (52781796288).

Almost surely, 2211122100121 is an apocalyptic number.

It is an amenable number.

211122100121 is a deficient number, since it is larger than the sum of its proper divisors (5085031).

211122100121 is an equidigital number, since it uses as much as digits as its factorization.

211122100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5085030.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 211122100121 its reverse (121001221112), we get a palindrome (332123321233).

The spelling of 211122100121 in words is "two hundred eleven billion, one hundred twenty-two million, one hundred thousand, one hundred twenty-one".

Divisors: 1 41863 5043167 211122100121