Base | Representation |
---|---|
bin | 110000000000010001100101… |
… | …011001010100110111010011 |
3 | 1000200112100211011111002121112 |
4 | 300000101211121110313103 |
5 | 210133033213031240201 |
6 | 2025005312130243535 |
7 | 62320200062165444 |
oct | 6000214531246723 |
9 | 1020470734432545 |
10 | 211125113540051 |
11 | 612a8726633737 |
12 | 1b8195654265ab |
13 | 90a6022100629 |
14 | 3a1c71d6bb2cb |
15 | 1961cae5d20bb |
hex | c00465654dd3 |
211125113540051 has 4 divisors (see below), whose sum is σ = 211469526450192. Its totient is φ = 210780700629912.
The previous prime is 211125113540041. The next prime is 211125113540057. The reversal of 211125113540051 is 150045311521112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211125113540051 - 246 = 140756369362387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211125113540057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172206454151 + ... + 172206455376.
It is an arithmetic number, because the mean of its divisors is an integer number (52867381612548).
Almost surely, 2211125113540051 is an apocalyptic number.
211125113540051 is a deficient number, since it is larger than the sum of its proper divisors (344412910141).
211125113540051 is an equidigital number, since it uses as much as digits as its factorization.
211125113540051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 344412910140.
The product of its (nonzero) digits is 6000, while the sum is 32.
The spelling of 211125113540051 in words is "two hundred eleven trillion, one hundred twenty-five billion, one hundred thirteen million, five hundred forty thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •