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2111300201323 = 9895072133689
BaseRepresentation
bin11110101110010011010…
…011000110101101101011
321110211122010210220020201
4132232103103012231223
5234042420322420243
64253530134333031
7305351662414645
oct36562323065553
97424563726221
102111300201323
11744440a16445
122a12261ba177
13124130239a71
147428a607895
1539dbe30504d
hex1eb934c6b6b

2111300201323 has 4 divisors (see below), whose sum is σ = 2111303324520. Its totient is φ = 2111297078128.

The previous prime is 2111300201287. The next prime is 2111300201327. The reversal of 2111300201323 is 3231020031112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111300201323 - 225 = 2111266646891 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2111300201323.

It is not an unprimeable number, because it can be changed into a prime (2111300201327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77338 + ... + 2056351.

It is an arithmetic number, because the mean of its divisors is an integer number (527825831130).

Almost surely, 22111300201323 is an apocalyptic number.

2111300201323 is a deficient number, since it is larger than the sum of its proper divisors (3123197).

2111300201323 is an equidigital number, since it uses as much as digits as its factorization.

2111300201323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3123196.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2111300201323 its reverse (3231020031112), we get a palindrome (5342320232435).

The spelling of 2111300201323 in words is "two trillion, one hundred eleven billion, three hundred million, two hundred one thousand, three hundred twenty-three".

Divisors: 1 989507 2133689 2111300201323