Base | Representation |
---|---|
bin | 10011101010011011… |
… | …101101100000110001 |
3 | 2000111101211122000021 |
4 | 103222123231200301 |
5 | 321214412031113 |
6 | 13411004523441 |
7 | 1345125361534 |
oct | 235233554061 |
9 | 60441748007 |
10 | 21113002033 |
11 | 8a54814a12 |
12 | 4112850581 |
13 | 1cb615b716 |
14 | 104404aa1b |
15 | 83881e48d |
hex | 4ea6ed831 |
21113002033 has 4 divisors (see below), whose sum is σ = 21117970548. Its totient is φ = 21108033520.
The previous prime is 21113001991. The next prime is 21113002091. The reversal of 21113002033 is 33020031112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 821854224 + 20291147809 = 28668^2 + 142447^2 .
It is a cyclic number.
It is not a de Polignac number, because 21113002033 - 233 = 12523067441 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21113001998 and 21113002016.
It is not an unprimeable number, because it can be changed into a prime (21113002133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2477878 + ... + 2486383.
It is an arithmetic number, because the mean of its divisors is an integer number (5279492637).
Almost surely, 221113002033 is an apocalyptic number.
It is an amenable number.
21113002033 is a deficient number, since it is larger than the sum of its proper divisors (4968515).
21113002033 is an equidigital number, since it uses as much as digits as its factorization.
21113002033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4968514.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 21113002033 its reverse (33020031112), we get a palindrome (54133033145).
The spelling of 21113002033 in words is "twenty-one billion, one hundred thirteen million, two thousand, thirty-three".
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