Base | Representation |
---|---|
bin | 11110101110010011011… |
… | …110001011001010011011 |
3 | 21110211122100021022210002 |
4 | 132232103132023022123 |
5 | 234042422043300011 |
6 | 4253530320443215 |
7 | 305352026162015 |
oct | 36562336131233 |
9 | 7424570238702 |
10 | 2111303103131 |
11 | 744442618632 |
12 | 2a122717950b |
13 | 124130a14801 |
14 | 7428ab611b5 |
15 | 39dbe6c9c3b |
hex | 1eb9378b29b |
2111303103131 has 2 divisors, whose sum is σ = 2111303103132. Its totient is φ = 2111303103130.
The previous prime is 2111303103127. The next prime is 2111303103193. The reversal of 2111303103131 is 1313013031112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111303103131 - 22 = 2111303103127 is a prime.
It is a super-2 number, since 2×21113031031312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2111303103121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055651551565 + 1055651551566.
It is an arithmetic number, because the mean of its divisors is an integer number (1055651551566).
Almost surely, 22111303103131 is an apocalyptic number.
2111303103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111303103131 is an equidigital number, since it uses as much as digits as its factorization.
2111303103131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 2111303103131 its reverse (1313013031112), we get a palindrome (3424316134243).
The spelling of 2111303103131 in words is "two trillion, one hundred eleven billion, three hundred three million, one hundred three thousand, one hundred thirty-one".
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