Base | Representation |
---|---|
bin | 10011101010011011… |
… | …110100101011101011 |
3 | 2000111101220010022001 |
4 | 103222123310223223 |
5 | 321214414001103 |
6 | 13411005311431 |
7 | 1345125543262 |
oct | 235233645353 |
9 | 60441803261 |
10 | 21113031403 |
11 | 8a54834a92 |
12 | 4112865577 |
13 | 1cb616bbb9 |
14 | 10440575d9 |
15 | 83882801d |
hex | 4ea6f4aeb |
21113031403 has 2 divisors, whose sum is σ = 21113031404. Its totient is φ = 21113031402.
The previous prime is 21113031377. The next prime is 21113031419. The reversal of 21113031403 is 30413031112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21113031403 - 25 = 21113031371 is a prime.
It is not a weakly prime, because it can be changed into another prime (21113031473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556515701 + 10556515702.
It is an arithmetic number, because the mean of its divisors is an integer number (10556515702).
Almost surely, 221113031403 is an apocalyptic number.
21113031403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113031403 is an equidigital number, since it uses as much as digits as its factorization.
21113031403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 21113031403 its reverse (30413031112), we get a palindrome (51526062515).
The spelling of 21113031403 in words is "twenty-one billion, one hundred thirteen million, thirty-one thousand, four hundred three".
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