21113101344033 has 24 divisors (see below), whose sum is σ = 30512409360576. Its totient is φ = 14068152165600.

The previous prime is 21113101343981. The next prime is 21113101344091. The reversal of 21113101344033 is 33044310131112.

21113101344033 is a `hidden beast` number, since 2 + 1 + 1 + 1 + 310 + 1 + 344 + 0 + 3 + 3 = 666.

It is not a de Polignac number, because 21113101344033 - 2⁶ = 21113101343969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21113101343988 and 21113101344006.

It is not an unprimeable number, because it can be changed into a prime (21113101344133) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 470338716 + ... + 470383602.

It is an arithmetic number, because the mean of its divisors is an integer number (1271350390024).

Almost surely, 2^{21113101344033} is an apocalyptic number.

It is an amenable number.

21113101344033 is a deficient number, since it is larger than the sum of its proper divisors (9399308016543).

21113101344033 is a wasteful number, since it uses less digits than its factorization.

21113101344033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70645 (or 70642 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 21113101344033 its reverse (33044310131112), we get a palindrome (54157411475145).

The spelling of 21113101344033 in words is "twenty-one trillion, one hundred thirteen billion, one hundred one million, three hundred forty-four thousand, thirty-three".