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21113102001 = 37037700667
BaseRepresentation
bin10011101010011100…
…000101111010110001
32000111102000201010210
4103222130011322301
5321214423231001
613411011014333
71345126256145
oct235234057261
960442021123
1021113102001
118a54883032
12411289a3a9
131cb6195084
141044075225
1583883ddd6
hex4ea705eb1

21113102001 has 4 divisors (see below), whose sum is σ = 28150802672. Its totient is φ = 14075401332.

The previous prime is 21113101957. The next prime is 21113102041. The reversal of 21113102001 is 10020131112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21113102001 - 210 = 21113100977 is a prime.

It is a super-2 number, since 2×211131020012 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21113102041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3518850331 + ... + 3518850336.

It is an arithmetic number, because the mean of its divisors is an integer number (7037700668).

Almost surely, 221113102001 is an apocalyptic number.

It is an amenable number.

21113102001 is a deficient number, since it is larger than the sum of its proper divisors (7037700671).

21113102001 is an equidigital number, since it uses as much as digits as its factorization.

21113102001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7037700670.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 21113102001 its reverse (10020131112), we get a palindrome (31133233113).

The spelling of 21113102001 in words is "twenty-one billion, one hundred thirteen million, one hundred two thousand, one".

Divisors: 1 3 7037700667 21113102001