2111311121131 has 2 divisors, whose sum is σ = 2111311121132. Its totient is φ = 2111311121130.

The previous prime is 2111311121113. The next prime is 2111311121167. The reversal of 2111311121131 is 1311211131112.

Together with previous prime (2111311121113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a m-pointer prime, because the next prime (2111311121167) can be obtained adding 2111311121131 to its product of digits (36).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2111311121131 - 2³⁵ = 2076951382763 is a prime.

It is a super-2 number, since 2×2111311121131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2111311121099 and 2111311121108.

It is not a weakly prime, because it can be changed into another prime (2111311121431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655560565 + 1055655560566.

It is an arithmetic number, because the mean of its divisors is an integer number (1055655560566).

Almost surely, 2^{2111311121131} is an apocalyptic number.

2111311121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111311121131 is an equidigital number, since it uses as much as digits as its factorization.

2111311121131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 36, while the sum is 19.

Adding to 2111311121131 its reverse (1311211131112), we get a palindrome (3422522252243).

It can be divided in two parts, 21113 and 11121131, that added together give a square (11142244 = 3338²).

The spelling of 2111311121131 in words is "two trillion, one hundred eleven billion, three hundred eleven million, one hundred twenty-one thousand, one hundred thirty-one".