Base | Representation |
---|---|
bin | 11110101110010100011… |
… | …111101011001010011001 |
3 | 21110211200112120200011221 |
4 | 132232110133223022121 |
5 | 234042440442223221 |
6 | 4253532132452041 |
7 | 305352325134412 |
oct | 36562437531231 |
9 | 7424615520157 |
10 | 2111320273561 |
11 | 744451285a74 |
12 | 2a1230a7a021 |
13 | 124134447025 |
14 | 7428d150809 |
15 | 39dc0e6c541 |
hex | 1eb947eb299 |
2111320273561 has 2 divisors, whose sum is σ = 2111320273562. Its totient is φ = 2111320273560.
The previous prime is 2111320273529. The next prime is 2111320273591. The reversal of 2111320273561 is 1653720231112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1959036918336 + 152283355225 = 1399656^2 + 390235^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111320273561 - 25 = 2111320273529 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111320273501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055660136780 + 1055660136781.
It is an arithmetic number, because the mean of its divisors is an integer number (1055660136781).
Almost surely, 22111320273561 is an apocalyptic number.
It is an amenable number.
2111320273561 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111320273561 is an equidigital number, since it uses as much as digits as its factorization.
2111320273561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 2111320273561 in words is "two trillion, one hundred eleven billion, three hundred twenty million, two hundred seventy-three thousand, five hundred sixty-one".
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