Base | Representation |
---|---|
bin | 1001100110011110011001… |
… | …11110101101110110101011 |
3 | 2202202101212102210000001221 |
4 | 10303033030332231312223 |
5 | 10231404320013041101 |
6 | 112523134403122511 |
7 | 4306243600366246 |
oct | 463171476556653 |
9 | 82671772700057 |
10 | 21113203252651 |
11 | 68000718a8184 |
12 | 244ba69073437 |
13 | ba1c745b6633 |
14 | 52dc5507c25d |
15 | 269309a36aa1 |
hex | 1333ccfaddab |
21113203252651 has 2 divisors, whose sum is σ = 21113203252652. Its totient is φ = 21113203252650.
The previous prime is 21113203252597. The next prime is 21113203252657. The reversal of 21113203252651 is 15625230231112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21113203252651 - 239 = 20563447438763 is a prime.
It is a super-2 number, since 2×211132032526512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21113203252657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556601626325 + 10556601626326.
It is an arithmetic number, because the mean of its divisors is an integer number (10556601626326).
Almost surely, 221113203252651 is an apocalyptic number.
21113203252651 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113203252651 is an equidigital number, since it uses as much as digits as its factorization.
21113203252651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 21113203252651 its reverse (15625230231112), we get a palindrome (36738433483763).
The spelling of 21113203252651 in words is "twenty-one trillion, one hundred thirteen billion, two hundred three million, two hundred fifty-two thousand, six hundred fifty-one".
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