2111321023131 has 4 divisors (see below), whose sum is σ = 2815094697512. Its totient is φ = 1407547348752.

The previous prime is 2111321023121. The next prime is 2111321023169. The reversal of 2111321023131 is 1313201231112.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2111321023131 - 2⁵ = 2111321023099 is a prime.

It is a super-2 number, since 2×2111321023131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2111321023098 and 2111321023107.

It is not an unprimeable number, because it can be changed into a prime (2111321023121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351886837186 + ... + 351886837191.

It is an arithmetic number, because the mean of its divisors is an integer number (703773674378).

Almost surely, 2^{2111321023131} is an apocalyptic number.

2111321023131 is a deficient number, since it is larger than the sum of its proper divisors (703773674381).

2111321023131 is an equidigital number, since it uses as much as digits as its factorization.

2111321023131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 703773674380.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2111321023131 its reverse (1313201231112), we get a palindrome (3424522254243).

The spelling of 2111321023131 in words is "two trillion, one hundred eleven billion, three hundred twenty-one million, twenty-three thousand, one hundred thirty-one".