Base | Representation |
---|---|
bin | 11110101110010100101… |
… | …111011011001000011011 |
3 | 21110211200211100102121121 |
4 | 132232110233123020123 |
5 | 234042443021332303 |
6 | 4253532401150111 |
7 | 305352405211312 |
oct | 36562457331033 |
9 | 7424624312547 |
10 | 2111324402203 |
11 | 744453645975 |
12 | 2a123232b337 |
13 | 124135261303 |
14 | 7428d907279 |
15 | 39dc14d59bd |
hex | 1eb94bdb21b |
2111324402203 has 2 divisors, whose sum is σ = 2111324402204. Its totient is φ = 2111324402202.
The previous prime is 2111324402189. The next prime is 2111324402233. The reversal of 2111324402203 is 3022044231112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111324402203 - 229 = 2110787531291 is a prime.
It is a super-2 number, since 2×21113244022032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2111324402233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055662201101 + 1055662201102.
It is an arithmetic number, because the mean of its divisors is an integer number (1055662201102).
Almost surely, 22111324402203 is an apocalyptic number.
2111324402203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111324402203 is an equidigital number, since it uses as much as digits as its factorization.
2111324402203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2111324402203 its reverse (3022044231112), we get a palindrome (5133368633315).
The spelling of 2111324402203 in words is "two trillion, one hundred eleven billion, three hundred twenty-four million, four hundred two thousand, two hundred three".
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