Base | Representation |
---|---|
bin | 11110101110010100101… |
… | …111100101000111110001 |
3 | 21110211200211102111202002 |
4 | 132232110233211013301 |
5 | 234042443024134441 |
6 | 4253532402103345 |
7 | 305352405441515 |
oct | 36562457450761 |
9 | 7424624374662 |
10 | 2111324443121 |
11 | 744453673693 |
12 | 2a123234ab55 |
13 | 124135276b1a |
14 | 7428d918145 |
15 | 39dc14e2b9b |
hex | 1eb94be51f1 |
2111324443121 has 2 divisors, whose sum is σ = 2111324443122. Its totient is φ = 2111324443120.
The previous prime is 2111324443103. The next prime is 2111324443153. The reversal of 2111324443121 is 1213444231112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1582702383025 + 528622060096 = 1258055^2 + 727064^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111324443121 - 214 = 2111324426737 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111324443021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055662221560 + 1055662221561.
It is an arithmetic number, because the mean of its divisors is an integer number (1055662221561).
Almost surely, 22111324443121 is an apocalyptic number.
It is an amenable number.
2111324443121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111324443121 is an equidigital number, since it uses as much as digits as its factorization.
2111324443121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4608, while the sum is 29.
Adding to 2111324443121 its reverse (1213444231112), we get a palindrome (3324768674233).
The spelling of 2111324443121 in words is "two trillion, one hundred eleven billion, three hundred twenty-four million, four hundred forty-three thousand, one hundred twenty-one".
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