211133113131 has 4 divisors (see below), whose sum is σ = 281510817512. Its totient is φ = 140755408752.

The previous prime is 211133113129. The next prime is 211133113151. The reversal of 211133113131 is 131311331112.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 211133113131 - 2¹ = 211133113129 is a prime.

It is a super-2 number, since 2×211133113131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211133113098 and 211133113107.

It is not an unprimeable number, because it can be changed into a prime (211133113151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35188852186 + ... + 35188852191.

It is an arithmetic number, because the mean of its divisors is an integer number (70377704378).

Almost surely, 2^211133113131 is an apocalyptic number.

211133113131 is a deficient number, since it is larger than the sum of its proper divisors (70377704381).

211133113131 is an equidigital number, since it uses as much as digits as its factorization.

211133113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70377704380.

The product of its digits is 162, while the sum is 21.

Adding to 211133113131 its reverse (131311331112), we get a palindrome (342444444243).

The spelling of 211133113131 in words is "two hundred eleven billion, one hundred thirty-three million, one hundred thirteen thousand, one hundred thirty-one".