2111332012033 has 4 divisors (see below), whose sum is σ = 2112779122480. Its totient is φ = 2109884901588.

The previous prime is 2111332011941. The next prime is 2111332012037. The reversal of 2111332012033 is 3302102331112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2111332012033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2111332011995 and 2111332012013.

It is not an unprimeable number, because it can be changed into a prime (2111332012037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723553035 + ... + 723555952.

It is an arithmetic number, because the mean of its divisors is an integer number (528194780620).

Almost surely, 2^{2111332012033} is an apocalyptic number.

It is an amenable number.

2111332012033 is a deficient number, since it is larger than the sum of its proper divisors (1447110447).

2111332012033 is a wasteful number, since it uses less digits than its factorization.

2111332012033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1447110446.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 2111332012033 its reverse (3302102331112), we get a palindrome (5413434343145).

The spelling of 2111332012033 in words is "two trillion, one hundred eleven billion, three hundred thirty-two million, twelve thousand, thirty-three".