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21113331113 = 73016190159
BaseRepresentation
bin10011101010011100…
…111101110110101001
32000111102110100102102
4103222130331312221
5321220003043423
613411015543145
71345131232130
oct235234756651
960442410372
1021113331113
118a54a1a186
12411298aab5
131cb6245444
1410440d4917
15838886c28
hex4ea73dda9

21113331113 has 4 divisors (see below), whose sum is σ = 24129521280. Its totient is φ = 18097140948.

The previous prime is 21113331077. The next prime is 21113331119. The reversal of 21113331113 is 31113331112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21113331113 - 212 = 21113327017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (21113331119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1508095073 + ... + 1508095086.

It is an arithmetic number, because the mean of its divisors is an integer number (6032380320).

Almost surely, 221113331113 is an apocalyptic number.

It is an amenable number.

21113331113 is a deficient number, since it is larger than the sum of its proper divisors (3016190167).

21113331113 is an equidigital number, since it uses as much as digits as its factorization.

21113331113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3016190166.

The product of its digits is 162, while the sum is 20.

Adding to 21113331113 its reverse (31113331112), we get a palindrome (52226662225).

Subtracting 21113331113 from its reverse (31113331112), we obtain a palindrome (9999999999).

The spelling of 21113331113 in words is "twenty-one billion, one hundred thirteen million, three hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 7 3016190159 21113331113